Bijection entre P(N) et [0,1]
Publié : jeu. 20/02/2025 09:30
Bijection entre P(N) et [0,1]
f: P(N) -> [0,1]
∅ -> 0
N -> 1
A -> 0,b1b2b3...bn ... ;développement binaire
où
bn = 1 si n ∈A
bn = 0 si non
A={1,4,5,7,8} -> 0,10011011
A={2,4,6,8,...} -> 0,01010101....; infini
g: [0,1] -> P(N)
0 -> ∅
1 -> N
0,b1b2b3...bn ... -> A
n si bn = 1
0,01100101 -> A={2,3,6,8}
0,101010101.... -> A={1,3,5,7,9,....} ; infini
fog = id
gof = id
f: P(N) -> [0,1]
∅ -> 0
N -> 1
A -> 0,b1b2b3...bn ... ;développement binaire
où
bn = 1 si n ∈A
bn = 0 si non
A={1,4,5,7,8} -> 0,10011011
A={2,4,6,8,...} -> 0,01010101....; infini
g: [0,1] -> P(N)
0 -> ∅
1 -> N
0,b1b2b3...bn ... -> A
n si bn = 1
0,01100101 -> A={2,3,6,8}
0,101010101.... -> A={1,3,5,7,9,....} ; infini
fog = id
gof = id